6b^2+26b-20=0

Solution for 6b^2+26b-20=0 equation:

6b^2+26b-20=0

a = 6; b = 26; c = -20;
Δ = b2-4ac
Δ = 262-4·6·(-20)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-34}{2*6}=\frac{-60}{12}
=-5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+34}{2*6}=\frac{8}{12}
=2/3
$